In this program we compute subtraction of two matrices A and B which has same order. First we ask user to enter order or size of matrix, then enter numbers for matrix A and B. In this elements of matrix B subtract from corresponding elements of matrix A . After that gives resultant matrix.
To understand the strategy, let us have look at the dummy matrices. Suppose matrices have order 3×3.
Also Read: Program for multiplication of two matrices
Matrix A :
6 5 7
9 8 6
4 3 8
Matrix B :
1 2 3
4 3 2
2 1 6
Resultant Matrix is subtraction of matrices A and B :
5 3 4
5 5 4
2 2 2
Also Read: Program for addition of two matrices
#include<iostream.h>
#include<conio.h>
int main()
{
clrscr();
int a[10][10];
int b[10][10];
int x,y,i,j;
cout<<“\nEnter the number of rows and columns :::\n\n”;
cin>>x>>y;
cout<<“\n\nEnter elements for Matrix A :::\n\n”;
for(i=0;i<x;i++)
{
for(j=0;j<y;j++)
{
cin>>a[i][j];
}
cout<<“\n”;
}
cout<<“\n\nEnter elements for Matrix B :::\n\n”;
for(i=0;i<x;i++)
{
for(j=0;j<y;j++)
{
cin>>b[i][j];
}
cout<<“\n”;
}
cout<<“\n\nMatrix A :\n\n”;
for(i=0;i<x;i++)
{
for(j=0;j<y;j++)
{
cout<<“\t”<<a[i][j];
}
cout<<“\n\n”;
}
cout<<“\n\nMatrix B :\n\n”;
for(i=0;i<x;i++)
{
for(j=0;j<y;j++)
{
cout<<“\t”<<b[i][j];
}
cout<<“\n\n”;
}
cout<<“\n\nSubtraction of Matrix A and Matrix B :\n\n”;
for(i=0;i<x;i++)
{
for(j=0;j<y;j++)
{
cout<<“\t”<<a[i][j]-b[i][j];
}
cout<<“\n\n”;
}
getch();
return 0;
}
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